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Can you look for the string, pass the results to a second search for the
%\s, then pass the non-positives to the the handler? It's a 2 step but
it looks like it's the only way since it's a two step question (does
this exist AND NOT begin with ).


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<ul><li><strong>References</strong>:
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<li><strong><a name="00130" href="msg00130.html">[ale] Yet another regex question</a></strong>
<ul><li><em>From:</em> cfowler at outpostsentinel.com (Christopher Fowler)</li></ul></li>
<li><strong><a name="00142" href="msg00142.html">[ale] Yet another regex question</a></strong>
<ul><li><em>From:</em> esoteric at 3times25.net (Geoffrey)</li></ul></li>
<li><strong><a name="00146" href="msg00146.html">[ale] Yet another regex question</a></strong>
<ul><li><em>From:</em> cfowler at outpostsentinel.com (Christopher Fowler)</li></ul></li>
<li><strong><a name="00147" href="msg00147.html">[ale] Yet another regex question</a></strong>
<ul><li><em>From:</em> esoteric at 3times25.net (Geoffrey)</li></ul></li>
<li><strong><a name="00148" href="msg00148.html">[ale] Yet another regex question</a></strong>
<ul><li><em>From:</em> cfowler at outpostsentinel.com (Christopher Fowler)</li></ul></li>
<li><strong><a name="00149" href="msg00149.html">[ale] Yet another regex question</a></strong>
<ul><li><em>From:</em> cfowler at outpostsentinel.com (Christopher Fowler)</li></ul></li>
<li><strong><a name="00150" href="msg00150.html">[ale] Yet another regex question</a></strong>
<ul><li><em>From:</em> cfowler at outpostsentinel.com (Christopher Fowler)</li></ul></li>
</ul></li></ul>
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