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*To*: [email protected]*Subject*: RE: DATACENTER: quick question*From*: Sean Donelan <[email protected]>*Date*: Sun, 14 Mar 1999 16:57:09 -0600*Cc*: [email protected]*Delivered-to*: [email protected]*Delivered-to*: [email protected]*Sender*: [email protected]

```
Good point. This is a bit like asking about frictionless billard
tables. The real world is a lot more complicated, and a real electrical
engineer is recommended.
Its been a long time since college, the basic equation for true power
on three phase is
Watts = Amps x Voltage x PowerFactor x 1.732
For apparent power, leave out the power factor. But this is just a
rule of thumb. There are all sorts of assumptions. If any of the
assumptions are not true, the equations get very hairy. You better
be comfortable with greek letters, Sin and Cosine's in your equations.
Peter Galbavy [mailto:[email protected]] writes:
>On Sun, Mar 14, 1999 at 12:51:27PM -0800, Shawn Blosser wrote:
>> One more quick thing. If I do have 3000 amps @ 480volts 3-phase, How
>> much power can I get out of that circuit (in watts)? Does the standard
>> relationship p=va work here?
>>
>> If so I would have 1.4Mwatts (or 1400kVA)? Does the 3-phase add
>> something to the equation?
>
>It worries me sometimes when I see people asking questions about
>megawatts.
>It does :)
--
Sean Donelan, Data Research Associates, Inc, St. Louis, MO
Affiliation given for identification not representation
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